Solution
$$\frac{x+y}{x-y}=\frac{11}{1}$$
x+y = 11x-11y ==> 10x = 12y ==> 5x = 6y OR x = 6y/5.
We substitute this value in the given expression to get:
$$\frac{6y+3y}{\frac{6y}{5}-2y}=\frac{9y}{-\frac{4y}{5}}=-\frac{45}{4}$$.
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