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Question 24
If ABC is an equilateral triangle and D is a point on BC such that AD $$\bot$$ BC, then
Solution
Let each side of the triangle be 'x'
AD $$\bot$$ BC $$\Rightarrow$$ 'D' is midpoint of BC
BD=DC=$$\frac{x}{2}$$
then AD:BD=x:$$\frac{x}{2}$$=2:1
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