Question 24

If ABC is an equilateral triangle and D is a point on BC such that AD $$\bot$$ BC, then

Solution

Let each side of the triangle be 'x'

AD $$\bot$$ BC $$\Rightarrow$$ 'D' is midpoint of BC

BD=DC=$$\frac{x}{2}$$

then AD:BD=x:$$\frac{x}{2}$$=2:1

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