Question 24

Each interior angle of a regular octagon in radians is

Solution

Each angle of a regular Octagon = $$\frac{1}{8}(2n-4)$$right angle where n=no. of sides

= $$\frac{1}{8}(2\times8-4)\times90^\circ$$

= $$\frac{12\times90^\circ}{8}$$=$$135^\circ$$

$$180^\circ$$=$$\prod$$

$$135^\circ$$=$$\frac{\prod}{180}\times135^\circ$$=$$\frac{3\prod}{4}$$

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