Question 24

ΔABC is right angled at B. If m∠A = 45°, then find the value of (cosecC + 1/√3).

Solution

Sum of angles of $$\triangle$$ ABC = $$\angle A+\angle B+\angle C=180^\circ$$

=> $$45^\circ+90^\circ+\angle C=180^\circ$$

=> $$\angle C=180^\circ-135^\circ=45^\circ$$

To find : $$(\cosec C + \frac{1}{\sqrt3})$$

= $$cosec(45^\circ)+\frac{1}{\sqrt3}$$

= $$\sqrt2+\frac{1}{\sqrt3}=\frac{(\sqrt6+1)}{\sqrt3}$$

=> Ans - (D)

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