Question 23

In a college 200 students are randomly chosen. 140 like tea and 120 like Coffee and 70 like both tea and coffee. How many like neither tea nor coffee?

Solution

Tea - A, Coffee - B

n(A $$ \cup $$ B) = n(A) + n(B) - n (A $$ \cap $$ B)
n(A $$ \cup $$ B) = 140 + 120 - 70 = 190
Number of students who like tea or coffee = 190
Therefore, number of students who like neither tea nor coffee = 200 - 190 = 10

Answer is option D.

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CMAT 2022

In a college 200 students are randomly chosen. 140 like tea and 120 like Coffee and 70 like both tea and coffee. How many like neither tea nor coffee?

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