Question 23
If the numerator of a fraction be increased by 15% and its denominator be diminished by 8%, the value of the fraction is $$\frac{15}{16}$$, then the original fraction is
Solution
Let us assume the original fraction to be P/1.
Numerator increased by 15% and denominator decreased by 8%
==> $$\frac{P\times\ 1.15}{1\times\ 0.92}=\frac{15}{16}$$
==> $$P\times\ \frac{5}{4}=\frac{15}{16}$$
P = $$\frac{3}{4}$$
So, the original fraction was $$\frac{3}{4}$$
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