The Nyquist filter has impulse response given by

A

$$h(t) = \frac{\sin \left( \frac{\pi t}{T}\right)}{\left(\frac {\pi t}{T}\right)}$$

B

$$h(t) = \frac {1}{2} \left(\frac{\sin (\pi t)}{(\pi t)}\right)$$

C

$$h(t) = \frac{\sin \left({\pi t}\right)}{\left(\frac {\pi t}{T}\right)}$$

D

$$h(t) = \frac{\cos \left({\pi t}\right)}{\left(\frac {\pi t}{T}\right)}$$