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If a source of power $$4$$ kW produces $$10^{20}$$ photons/second, the radiation belong to a part of the spectrum called
Power ($$P$$) is defined as the total energy emitted by a radiation source per unit time. If a source emits $$n$$ photons per second, and each individual photon carries an energy $$E$$, the total power is given by:
$$P = n \cdot E$$
We are given the following values from the system:
Isolating the energy variable from the power equation:
$$E = \frac{P}{n}$$
Substituting our given parameters:
$$E = \frac{4 \times 10^3}{10^{20}} = 4 \times 10^{-17} \,\, \text{J}$$
According to Planck's quantum theory, the energy of a photon is related to its wavelength ($$\lambda$$) by the formula:
$$E = \frac{h \cdot c}{\lambda} \implies \lambda = \frac{h \cdot c}{E}$$
Where:
Substituting these universal constants into our wavelength equation:
$$\lambda = \frac{6.63 \times 10^{-34} \times 3 \times 10^8}{4 \times 10^{-17}}$$
$$\lambda = \frac{19.89 \times 10^{-26}}{4 \times 10^{-17}} \approx 4.97 \times 10^{-9} \,\, \text{m} = 4.97 \,\, \text{nm}$$
Let us look at the standard wavelength thresholds defining parts of the electromagnetic spectrum:
Since our calculated wavelength of $$\lambda \approx 4.97 \,\, \text{nm}$$ sits cleanly within the range of $$0.01 \,\, \text{nm}$$ to $$10 \,\, \text{nm}$$, the radiation belongs to the X-rays region.
Correct Option Key: Option A (X-rays)
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