take the hcf of 513,1134,1215 by taking factorization
$$513=3\times 3\times 3\times 19$$
$$1134=3\times 2\times 3\times 3\times 3\times 7$$
$$1215=3\times 3\times 3\times 3\times 3\times 5$$
by taking common
$$hcf=3\times 3\times 3=27$$
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