Solution
take the hcf of 513,1134,1215 by taking factorization
$$513=3\times 3\times 3\times 19$$
$$1134=3\times 2\times 3\times 3\times 3\times 7$$
$$1215=3\times 3\times 3\times 3\times 3\times 5$$
by taking common
$$hcf=3\times 3\times 3=27$$
Need AI Help?
Create a FREE account and get:
- Download RRB Study Material PDF
- 45+ RRB previous papers with solutions PDF
- 300+ Online RRB Tests for Free
