Question 22

A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4 : 5. The quantity of alcohol in the given mixture (in liters) is :

Let us assume the quantity of alcohol and water in the mixture to be 4x and 3x respectively.
After adding 5 litres of water, the new quantity of water becomes 3x+5 litres.
New ratio of alcohol and water is 4:5 
==> $$\frac{4x}{3x+5}=\frac{4}{5}$$
==> x = 2.5.
Volume of alcohol = 4x = 4*2.5 = 10 litres.

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