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S is the mid-point of the side QR of the triangle PQR and T is the mid point of QS. If O is the mid point of PT, then area of Δ QOT is equal to:
$$\frac{1}{2}$$ area of $$\triangle PQR$$
$$\frac{1}{4}$$ area of $$\triangle PQR$$
$$\frac{1}{6}$$ area of $$\triangle PQR$$
$$\frac{1}{8}$$ area of $$\triangle PQR$$
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