Which two numbers (not digits) should be interchanged to make the given equation correct?
$$( \sqrt{144} \div 4)^{3} + 6)^{2} - (28 \times 2) + 72 + (32 \div 8) \times 3 = 52$$

A

3 and 6

B

2 and 8

C

2 and 4

D

4 and 6