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$$\text{Top input} = \bar{A}$$
$$\text{Bottom input} = \bar{B}$$
Output $$Y$$ from the NAND gate configuration: $$Y = \overline{\bar{A} \cdot \bar{B}}$$
Applying De Morgan's Law ($$\overline{X \cdot Y} = \bar{X} + \bar{Y}$$):
$$Y = \overline{\bar{A}} + \overline{\bar{B}}$$
$$\implies Y = A + B \quad (\text{OR gate operation})$$
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