A soap bubble $$10\ \text{cm}$$ in radius, with a film thickness of $$\frac{10}{3}\times10^{-6}\ \text{cm}$$, is charged to a potential of $$80\ \text{V}$$. The bubble bursts and converts into a single spherical drop. Assuming that the soap solution is a good conductor, the potential at the surface of the drop is

A

$$2\ \text{kV}$$

B

$$4\ \text{kV}$$

C

$$6\ \text{kV}$$

D

$$8\ \text{kV}$$