Question 20
A boy travels 4 km towards south and then takes a left turn and travels another 3 km in that direction. How far and in which direction is he now from his original position?
Solution
Let the boy starts from point A and travels 4 km towards south to reach B and then takes a left turn and travels another 3 km east wards to finally reach point C.
Thus, $$(AC)^2=(AB)^2+(BC)^2$$
=> $$(AC)^2=(4)^2+(3)^2$$
=> $$(AC)^2=16+9=25$$
=> $$AC=\sqrt{25}=5$$ km
$$\therefore$$ He is 5 km in the south-east direction from his original position.
=> Ans - (B)
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