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What is the sum to infinity of the series,$$3+6x^{2}+9x^{4}+12x^{6}+$$........given $$\mid x$$ < 1 ?
$$\frac{3}{1+x^{2}}$$
$$\frac{3}{(1+x^{2})^{2}}$$
$$\frac{3}{(1-x^{2})^{2}}$$
$$\frac{3}{(1-x^{2})}$$
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