Calculate the value of $$\frac{\sqrt{3}}{(3+\sqrt{3})}$$ if $$\sqrt{3}=1.7320$$
Expression : $$\frac{\sqrt{3}}{(3+\sqrt{3})}$$ if $$\sqrt{3}=1.7320$$
Rationalizing the denominator :
=Â $$\frac{\sqrt{3}}{(3+\sqrt{3})}\times\frac{(3-\sqrt3)}{(3-\sqrt3)}$$
= $$\frac{\sqrt3(3-\sqrt3)}{(3)^2-(\sqrt3)^2}=\frac{3\sqrt3-3}{9-3}$$
= $$\frac{\sqrt3-1}{2}=\frac{(1.7320-1)}{2}$$
= $$\frac{0.7320}{2}=0.366$$
=> Ans - (A)
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