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In the figure, in $$\triangle ABC$$, $$\angle A = 80^\circ$$ and $$\angle ABC = 40^\circ$$. BD and CD bisect angles B and C, respectively. The values of $$x$$ and $$y$$ respectively are
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In $$\triangle ABC$$, $$\angle C = 180^\circ - 80^\circ - 40^\circ = 60^\circ$$. CD bisects $$\angle C$$, so $$x = 30$$, and BD bisects $$\angle B$$, so $$\angle DBC = 20^\circ$$. In $$\triangle BDC$$, $$y = 180 - 20 - 30 = 130$$.
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