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A $$5\ \text{m}$$ long ladder is placed against a wall. The foot of the ladder is $$3\ \text{m}$$ away from the base of the wall. How far up the wall does the top of the ladder reach?
The ladder, the wall and the ground form a right triangle with the ladder as hypotenuse. By Pythagoras, the height is $$\sqrt{5^2 - 3^2} = \sqrt{16} = 4\ \text{m}$$.
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