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Question 19
Find two consecutive numbers where thrice the first number is more than twice the second number by 5.
Solution
Let the consecutive numbers be x and (x + 1)
According to the question,
3x - 2(x + 1) = 5
3x - 2x - 2 = 5
x = 7.
So, two consecutive numbers is 7 and 8.
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