Question 185

If 64 + 14 = 5, 92 + 31 = 7, 26 + 11= 6, then 56 + 22= ?

Solution

The sum of digits of the second number is subtracted from the sum of digits of first number.

Eg = $$(6+4)-(1+4)=10-5=5$$

and $$(9+2)-(3+1)=11-4=7$$

and $$(2+6)-(1+1)=8-2=6$$

Similarly, $$(5+6)-(2+2)=11-4=7$$

=> Ans - (B)

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