If $$f : ℝ \rightarrow ℝ$$ and $$g : ℝ \rightarrow ℝ$$ be defined by $$f(x) = 6x + 8$$ and $$g(x) = \frac{x - 2}{3}$$, then $$f o  g(\frac{1}{2}) =$$

A

$$\frac{1}{5}$$

B

6

C

5

D

$$\frac{1}{6}$$