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Tension in the cable supporting a lift of weight ‘W’ and having an acceleration of ‘a’ while going upward is (gis acceleration due to gravity)
$$W\left(1 + \frac{a}{g}\right)$$
$$W\left(1 - \frac{a}{g}\right)$$
$$W\left(2 + \frac{a}{g}\right)$$
$$W\left(1 + \frac{2a}{g}\right)$$
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