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In the network shown below, switch is opened at t = 0 after long time. The current $$i_{L} (t)$$ for $$t > 0$$ is given as
$$e^{-2t}(2 \cos t+4 \sin t)A $$
$$e^{-2t}(3 \sin t-4 \cos t)A $$
$$e^{-2t}(- 4 \sin t+2 \cos t)A $$
$$e^{-2t}(2 \sin t-4 \cos t)A $$
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