Question 18
A right-angled triangle ABC is right-angled at B, and tan A = $$\dfrac{3}{4}$$. If AC = 25 cm, the length of BC is:
Solution
From Pythagoras theorem, $AC^2 = AB^2 + BC^2$
=> $BC^2 = AC^2 - AB^2$
=> $16x^2 = 625 - 9x^2$
=> $25x^2 = 625$
=> $x^2 = 25$
=> x = 5
Therefore, BC = 4x = 4*5 = 20 cm
From Pythagoras theorem, $AC^2 = AB^2 + BC^2$
=> $BC^2 = AC^2 - AB^2$
=> $16x^2 = 625 - 9x^2$
=> $25x^2 = 625$
=> $x^2 = 25$
=> x = 5
Therefore, BC = 4x = 4*5 = 20 cm
Create a FREE account and get:
- Download RRB Study Material PDF
- 45+ RRB previous papers with solutions PDF
- 300+ Online RRB Tests for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Quadratic Equations QuestionsCAT Inequalities QuestionsCAT Averages QuestionsCAT Linear Equations QuestionsCAT Percentages Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Quant Based DI QuestionsCAT Table with Missing values QuestionsCAT Selection With Condition QuestionsCAT Charts QuestionsCAT Routes And Networks Questions
