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A material has a young’s modulus of $$1.25 \times 10^{5}$$ $$\frac{N}{mm^{2}}$$ and a poisson’s ratio of 0.25. The bulk modulus of the material will be
$$83 \times 10^{5}$$ $$\frac{N}{mm^{2}}$$
$$0.83 \times 10^{5}$$ $$\frac{N}{mm^{2}}$$
$$8.3 \times 10^{3}$$ $$\frac{N}{mm^{2}}$$
$$8.3 \times 10^{5}$$ $$\frac{N}{mm^{2}}$$
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