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There are six teachers. Out of them, two teach physics, other two teach Chemistry and the rest two teach Mathematics. They have to stand in a row such that Physics, Chemistry and Mathematics teachers are always in a set. The numberof ways in which they can do, is :
There are 2 physics teacher.They can stand in a row in $$P(2,2)=2!=2\times1=2$$ ways
Similarly, the two Chemistry and Mathematics teacher can stand in 2 ways each.
These three sets can be arranged in themselves in $$3!=3\times2\times1=6$$ ways
=> Required number of ways = $$2\times2\times2\times6=48$$
=> Ans - (B)
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