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A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of $$4 \times 10^{-4}$$ A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V it should be connected to a resistance of:
Full-scale deflection current: $$I_g = 25 \times (4 \times 10^{-4}) = 10^{-2}\text{ A}$$
Voltmeter conversion formula: $$V = I_g(G + R)$$
$$2.5 = 10^{-2}(50 + R) \implies 250 = 50 + R$$
$$R = 200\ \Omega$$
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