Sign in
Please select an account to continue using cracku.in
↓ →
A cylindrical vessel of radius 4 cm contains water. A solid sphere of 3 cm radius is lowered into the water until it is completely immersed . The water level in the vessel will rise by :
The volume of the sphere = $$\dfrac{4}{3}\times\ \pi\ \times\ \left(3\right)^3=36\pi\ $$
Now, the water level will increase equal to the volume of the sphere.
Let the water level increasing by h cm.
Therefore, $$36\pi\ =\pi\ \times\ \left(4\right)^2\times h$$
$$h=\dfrac{9}{4}$$
Was this solution helpful?
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
