IBPS Clerk 11-Dec-2011 EZ 2nd

Question 160

$$4^{10} \times 64 \div 256 = 4^{?} \times 16$$

Solution

$$4^{10} \times 4^{3} \div 4^{4} = 4^{x} \times 4^{2}$$

$$ 4^{13-4-2} = 4^{x}$$

$$ 4^{7} = 4^{x}$$

x=7 (NOTA)

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