The total energy released in $$\alpha$$ decay of a stationary Radium nucleus $$^{226}\mathrm{Ra}$$, printed with mass $$116\ \mathrm{u}$$, is $$Q=4.9\ \text{MeV}$$. The mass of the $$\alpha$$ particle is $$m_\alpha=4\ \mathrm{u}$$. Then the correct statement is

A

energy of the recoiled daughter nucleus is nearly $$8.7\ \text{keV}$$

B

energy of the recoiled daughter nucleus is nearly $$4.81\ \text{MeV}$$

C

recoil speed of the daughter nucleus is $$2.74\times10^5\ \text{m s}^{-1}$$

D

speed of emitted $$\alpha$$ particle is nearly $$1.5\times10^6\ \text{m s}^{-1}$$