The sum of the squares of two odd numbers is 11570. The square of the smaller number is 5329. What is the other number?
let the two numbers be a and b , where b is the smaller number
$$(a)^2$$ + $$(b)^2$$ = 11570
$$(a)^2$$ + 5329 = 11570
$$(a)^2$$ = 6241 = 79 x 79
a = 79
Hence option D is correct
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