The length of a rectangle is halved, and its breadth is tripled. What is the percentage change in its area?
let original length = x and original breadth = y.
Original area of rectangle = xy.
new length =$$\frac{x}{2}$$ and new breadth=3y
New area = $$\frac{3xy}{2}$$
so,Increase in area = New area-original area = $$\frac{3xy}{2}$$−xy= $$\frac{xy}{2}$$
sp, Increase %
= $$\frac{ increase in area}{ original area}100$$
= $$\frac{\frac{xy}{2}}{xy}\times 100$$
= 50%
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