Question 16

Select the pair that does NOT belong in the following group.

$$(\sqrt{64},9), (\sqrt{81},10), (\sqrt{36}, 8), (\sqrt{121}, 12)$$

Solution

$$(\sqrt{64},9) =8^2 , 9$$

$$(\sqrt{81},10) =9^2 , 10$$

$$(\sqrt{36}, 8) gn =6^2 , 8$$

$$ (\sqrt{121}, 12) = 11^2 , 12$$

so wrong is =$$(\sqrt{36}, 8)$$

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