Question 16
Select the pair that does NOT belong in the following group.
$$(\sqrt{64},9), (\sqrt{81},10), (\sqrt{36}, 8), (\sqrt{121}, 12)$$
Solution
$$(\sqrt{64},9) =8^2 , 9$$
$$(\sqrt{81},10) =9^2 , 10$$
$$(\sqrt{36}, 8) gn =6^2 , 8$$
$$ (\sqrt{121}, 12) = 11^2 , 12$$
so wrong is =$$(\sqrt{36}, 8)$$
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