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The ascending order of the fractions
$$\frac{97}{103},\frac{99}{105},\frac{101}{108},\frac{103}{110}$$ is
$$\frac{103}{110}<\frac{101}{108}<\frac{97}{103}<\frac{99}{105}$$
$$\frac{101}{108}<\frac{97}{103}<\frac{103}{110}<\frac{99}{105}$$
$$\frac{103}{110}<\frac{97}{103}<\frac{101}{108}<\frac{99}{105}$$
$$\frac{101}{108}<\frac{103}{110}<\frac{97}{103}<\frac{99}{105}$$
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