Question 158

The perimeter of a rectangle whose length is 6rn more than its breadth is 84 m. What would be the area of a triangle whose base is equal to the diagonal of the rectangle and whose height is equal to the length of the rectangle ? (in m )

Solution

Breadth = b meters
Length = (b+6) meters

Perimeter = 4b+12 = 84, i.e. b = 18
b = 18, L = 24
Diagonal = 30 (3:4:5 Pythagoras triplet)

Triangle - base = 30, height = 24
Area = 12*30 = 360 square meters

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The perimeter of a rectangle whose length is 6rn more than its breadth is 84 m. What would be the area of a triangle whose base is equal to the diagonal of the rectangle and whose height is equal to the length of the rectangle ? (in m )

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