Question 158

$$(?)^{2}$$ % of $$650=(20)^{2}+(4)^{2}$$

Solution

Let the percentage be x%
$$(20)^{2} = 400$$
$$(4)^{2} = 16$$
$$(20)^{2}+(4)^{2} = 400+16 = 416$$
$$x^{2}\times650$$ =$$416$$
$$x^{2}=$$ $$\frac{416}{650}=0.64$$
$$x=8\%$$
Hence Option A is the correct answer.

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IBPS Clerk 04-Dec-2011 EZ 2nd

$$(?)^{2}$$ % of $$650=(20)^{2}+(4)^{2}$$

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