Instructions

In each of these questions a number series is given. In each series ‘’only one’’ number is wrong. Find out the ‘’wrong number’’

Question 157

4, 12, 42, 196, 1005, 6066, 42511

Solution

$$T_n = T_{n-1}*n + n^2$$

12 = $$4*2 + 2^2$$

45 = $$12*3 + 3^2$$

196 = $$45*4+4^2$$

and so on.

So 42 is the wrong term in the series.


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