IBPS Clerk 11-Dec-2011 NZ 1st

Question 157

$$(0.6)^{4} \times (0.36)^{2} \times (0.216) = (0.6)^{(?)}$$

Solution

$$(0.6)^{4}$$ * $$(0.6*0.6)^{2}$$ * (0.6*0.6*0.6)

$$(0.6)^{4}$$ * $$(0.6^{2})^{2}$$ * $$(0.6^{3})$$

$$(0.6)^{4+4+3}$$

$$(0.6)^{11}$$

Hence , x = 11

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