The compound A on treatment with Na gives B, and with $$PCl_{5}$$ gives C B and C react together to give diethyl ether. A, B and C are in the order

A

$$C_{2} H_{5} OH,C_{2} H_{5} ONa,C_{2} H_{5} Cl$$

B

$$C_{2} H_{5} Cl,C_{2} H_{6},C_{2} H_{5} OH$$

C

$$C_{2} H_{5} OH,C_{2} H_{5} Cl,C_{2} H_{5} ONa$$

D

$$C_{2} H_{5} OH,C_{2} H_{6},C_{2} H_{5} Cl$$