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The compound A on treatment with Na gives B, and with $$PCl_{5}$$ gives C B and C react together to give diethyl ether. A, B and C are in the order
$$C_{2} H_{5} OH,C_{2} H_{5} ONa,C_{2} H_{5} Cl$$
$$C_{2} H_{5} Cl,C_{2} H_{6},C_{2} H_{5} OH$$
$$C_{2} H_{5} OH,C_{2} H_{5} Cl,C_{2} H_{5} ONa$$
$$C_{2} H_{5} OH,C_{2} H_{6},C_{2} H_{5} Cl$$
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