Question 154

$$76\% of (?) - (11)^2 = 525$$

Solution

The question is supposed to be $$76\% of (?) - (11)^{2} = 525$$
Let the unknown term be $$x$$.
$$76$$% of $$x$$ = $$525+11^{2}$$=$$646$$
$$x$$=$$\frac{646\times100}{76}$$=$$850$$

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IBPS Clerk 04-Dec-2011 EZ 2nd

$$76\% of (?) - (11)^2 = 525$$

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