A and B together can complete a piece of work in 16 days. B alone can complete the same work in 24 days. In how many days can A alone complete the same work?
A's 1 day's work = $$\frac{1}{16} - \frac{1}{24}$$
= $$\frac{3 - 2}{48} = \frac{1}{48}$$
Hence, A alone will complete the work in 48 days.
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