Question 15

P can make a table in 16 days while Q can make it in 20 days. Q started the work and did that work for 5 days. In how many days P can complete the remaining work?

Solution

Let total number of work done = L.C.M. (16,20) = 80 units

P can make the table in 16 days, => P's efficiency = $$\frac{80}{16}=5$$ units/day

Q's efficiency = $$\frac{80}{20}=4$$ units/day

Now, Q worked alone for 5 days, => Work completed by Q = $$5\times4=20$$ units

Thus, work left = $$80-20=60$$ units

$$\therefore$$ Time taken by P to complete the remaining work = $$\frac{60}{5}=12$$ days

=> Ans - (B)

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