RRB ALP 21st Aug 2018 Shift-1

Question 15

If $$x^2 + kx + k = 0$$ has repeated roots, then the value of $$k$$ will satisfy:

Solution

For repeated root,

Discriminate Must be = 0

Thus, $$D = b^2 - 4ac$$

Here, b = k , a = 1 & c = k

=> $$k^2 - 4\times k$$ = 0

=> k(k-4) = 0

=> k = 4 or k = 0

Thus, value of k is Natural number

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