Question 15

If $$(1 + xy + x + y)^2 - (1 - xy + x - y)^2 = ky(1 + x)^2$$, then $$k$$ equals to

Solution

Factorising each bracket, $$1 + xy + x + y = (1 + x)(1 + y)$$ and $$1 - xy + x - y = (1 + x)(1 - y)$$. So the left side is $$(1 + x)^2[(1 + y)^2 - (1 - y)^2] = (1 + x)^2 (4y)$$. Comparing with $$ky(1 + x)^2$$ gives $$k = 4$$.

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