Question 15

Assuming that $$\sqrt{32\sqrt{32\sqrt{32.......}}}$$ is a real number, its value is

Solution
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Let $$\sqrt{32\sqrt{32\sqrt{32.......}}}$$ = x

$$\sqrt{32x}$$ = x

Squaring on both sides , we get 

32x=$$x^{2}$$

$$\therefore x$$ = 32

Hence B is the correct answer.

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