Assuming that $$\sqrt{32\sqrt{32\sqrt{32.......}}}$$ is a real number, its value is
Let $$\sqrt{32\sqrt{32\sqrt{32.......}}}$$ = x
$$\sqrt{32x}$$ = x
Squaring on both sides , we get
32x=$$x^{2}$$
$$\therefore x$$ = 32
Hence B is the correct answer.
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