A player can take a maximum of 4 chances to hit a bottle with a flying disc. The probability of hitting the bottle at the first, second, third and fourth shots are 0.1, 0.2, 0.35 and 0.45 respectively. What is the probability that the player hits the bottle with the flying disc?

The probability he hits the disc = Probability of hitting on any of the four shots

P = (Hitting of 1st) + (Not hitting on 1st shot*Hitting on 2nd shot) + (Not hitting on 1st and 2nd shot*Hitting on 3rd shot) + (Not hitting on 1st, 2nd and 3rd shot*Hitting on 4th shot)

We know that the Probability of not hitting at a shot = 1 - The probability of hitting the bottle at that shot

$$P = 0.1+\left(0.9\times0.2\right)+\left(0.9\times0.8\times0.35\right)+\left(0.9\times0.8\times0.65\times0.45\right)$$

$$P=0.1+0.18+0.252+0.2106$$

$$P=0.7426$$

Hence, the answer is Option C