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The following questions are based on the given information. A man sold 8500 articles in a span of four days. He sold 26% articles on day one. 250/o articles on day 2 and 32% articles on day 3. The remaining articles were sold on day 4.
Solution
Articles Sold on day 1 = $$\frac{26}{100}\times8500$$ = 2210
Articles Sold on day 2 = $$\frac{25}{100}\times8500$$ = 2125
Articles Sold on day 3 = $$\frac{32}{100}\times8500$$ = 2720
Total Articles sold in 3 days = 2210 + 2125 + 2720 = 7055
Difference between articles sold on day 3 and 1 is = 2720 - 2210 = 510
As no such option is available so the answer is option E
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