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If tan 22 $$\frac{1}{2}^\circ$$ =x,then the value of cos 67 $$\frac{1}{2}^\circ$$ is
$$\frac{x}{\sqrt{x^{2}+1}}$$
$$\frac{1}{\sqrt{x^{2}+1}}$$
$$\frac{x}{\sqrt{x^{2}-1}}$$
$$\frac{1}{\sqrt{x^{2}-1}}$$
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