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What number shall you get in the unit digit on solving the following problem :
$$\left\{ (6374)^{1793}\times(625)^{317}\times (341^{491}) \right\}$$
Unit digit ofΒ $$6374^{1793}\times625^{317}\times341^{491}\ $$ = Unit digit ofΒ $$4^{1793}\times5^{317}\times1^{491}\ $$ = unit digit of 4*5*1 = 0
Option A is the answer.
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